The value of lim(x →1)((ln(1 + x) - ln2)(3.4^x - 1 - 3x))/([(7 + x)^1/3 - (1 + 3x)^1/2].sin(x - 1)) is - Sarthaks eConnect | Largest Online Education Community
![algebra precalculus - $y = \ln x$ with their $x$ coordinates as $1,2$ and $t$ respectively - Mathematics Stack Exchange algebra precalculus - $y = \ln x$ with their $x$ coordinates as $1,2$ and $t$ respectively - Mathematics Stack Exchange](https://i.stack.imgur.com/cH0gt.jpg)
algebra precalculus - $y = \ln x$ with their $x$ coordinates as $1,2$ and $t$ respectively - Mathematics Stack Exchange
![calculus - How to evaluate $\int_{0}^{1}{\frac{x\ln(1+x)\ln(1+x^2)}{1+x^2}}dx$ - Mathematics Stack Exchange calculus - How to evaluate $\int_{0}^{1}{\frac{x\ln(1+x)\ln(1+x^2)}{1+x^2}}dx$ - Mathematics Stack Exchange](https://i.stack.imgur.com/6ZYkD.jpg)
calculus - How to evaluate $\int_{0}^{1}{\frac{x\ln(1+x)\ln(1+x^2)}{1+x^2}}dx$ - Mathematics Stack Exchange
![ln ( 1 + x ) - ln 2 ) left( 3.4 ^ { x - 1 } - 3 x right) ) (12) Evahuate ( lim _ { x rightarrow 1 } frac { ( ln ( 1 + x ) - ln 2 ) left( 3.4 ^ { x - 1 } - 3 x right) } { left[ ( 7 + x ) ^ { frac { 1 } { 3 } } - ( 1 + 3 x ) ^ { frac { 1 } { 2 } } right ... ln ( 1 + x ) - ln 2 ) left( 3.4 ^ { x - 1 } - 3 x right) ) (12) Evahuate ( lim _ { x rightarrow 1 } frac { ( ln ( 1 + x ) - ln 2 ) left( 3.4 ^ { x - 1 } - 3 x right) } { left[ ( 7 + x ) ^ { frac { 1 } { 3 } } - ( 1 + 3 x ) ^ { frac { 1 } { 2 } } right ...](https://toppr-doubts-media.s3.amazonaws.com/images/5203644/6a6e4b01-cd0e-431f-8f54-637d83a5fc2e.jpg)