If (x-1)4-16=0 then sum of non real complex values of x is - Sarthaks eConnect | Largest Online Education Community
![How do you solve the following system using substitution?: 1/x + 1/y = 3/4, 3/x - 1/y = 1/4 | Socratic How do you solve the following system using substitution?: 1/x + 1/y = 3/4, 3/x - 1/y = 1/4 | Socratic](https://useruploads.socratic.org/HaPTlYA0T0WGkM2N5EuM_mat2.jpg.jpeg)
How do you solve the following system using substitution?: 1/x + 1/y = 3/4, 3/x - 1/y = 1/4 | Socratic
![Dominio delle funzioni: {y}={\frac{{{e}^{x}}}{{{{\log}^{2}{x}}-{4 }}}};{y}=\sqrt{{\sqrt{{{4}{x}^{2}+{7}{x}-{2}}}+{3}-{2}{x }}};{y}=\sqrt{{{\frac{{{{\log}_{{\frac{1}{{2}}}}{x }}+{3}}}{{{{\log}_{{3}}{\left({x}-{1}\right)}}-{1}}}}}} Dominio delle funzioni: {y}={\frac{{{e}^{x}}}{{{{\log}^{2}{x}}-{4 }}}};{y}=\sqrt{{\sqrt{{{4}{x}^{2}+{7}{x}-{2}}}+{3}-{2}{x }}};{y}=\sqrt{{{\frac{{{{\log}_{{\frac{1}{{2}}}}{x }}+{3}}}{{{{\log}_{{3}}{\left({x}-{1}\right)}}-{1}}}}}}](https://www.skuola.net/news_foto/2017/10/dominio-1647.jpg)
Dominio delle funzioni: {y}={\frac{{{e}^{x}}}{{{{\log}^{2}{x}}-{4 }}}};{y}=\sqrt{{\sqrt{{{4}{x}^{2}+{7}{x}-{2}}}+{3}-{2}{x }}};{y}=\sqrt{{{\frac{{{{\log}_{{\frac{1}{{2}}}}{x }}+{3}}}{{{{\log}_{{3}}{\left({x}-{1}\right)}}-{1}}}}}}
![How to solve the following equations? 1. 5+ x= 1/2-1/3'" "2. 1/4+x =1/2-1/3," "3. 1-1/2+m=3/4+1/2 | Socratic How to solve the following equations? 1. 5+ x= 1/2-1/3'" "2. 1/4+x =1/2-1/3," "3. 1-1/2+m=3/4+1/2 | Socratic](https://useruploads.socratic.org/ltBETTImRsyYZHTmgqCW_IMG_5D5A6D8AFAA2-1.jpeg)